> tmp <- data.frame(matrix(rnorm(30), 10, 3,
dimnames=list(letters[1:10],
c("company", "person", "salary"))))
> tmp
company person salary
a -1.04590176 -0.7841855 1.07150503
b -1.06643101 0.6545647 0.43920454
c 0.72894531 -1.3812867 0.41313659
d -0.39265263 -0.3871271 0.69404325
e 0.54028124 0.7124772 0.66630904
f -1.46931714 -0.3823353 0.03069797
g -0.33283666 -0.6351862 0.37920017
h -0.79977129 0.2605315 0.92373900
i 0.80614119 0.3727227 -1.16560563
j 0.03165012 0.4690400 -0.81966285
> order(tmp$person, decreasing=TRUE)[1:min(5, length(tmp$person))]
[1] 5 2 10 9 8
> tmp[order(tmp$person, decreasing=TRUE)[1:min(5, length(tmp$person))],]
company person salary
e 0.54028124 0.7124772 0.6663090
b -1.06643101 0.6545647 0.4392045
j 0.03165012 0.4690400 -0.8196628
i 0.80614119 0.3727227 -1.1656056
h -0.79977129 0.2605315 0.9237390
You can easily write a function for that.
top <- function(DF, varname, howmany) {}
On Thu, Sep 16, 2010 at 11:39 AM, Tan, Richard <r...@panagora.com> wrote:
> Hi, is there an R function like sql's TOP key word?
>
> I have a dataframe that has 3 columns: company, person, salary
>
> How do I get top 5 highest paid person for each company, and if I have
> fewer than 5 people for a company, just return all of them?
>
> Thanks,
>
> Richard
>
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
