that seems right....
order() gives you the indexes "idx" such that x[idx] == sort(x)
> set.seed(123)
> x <- rnorm(10)
> idx <- order(x)
> identical(x[idx], sort(x))
[1] TRUE
best
b
On Jan 28, 2008, at 8:19 PM, Waverley wrote:
I have a data vector as following:
z
[1] 183.1370 201.9610 113.7250 140.7840 156.2750 42.1569 42.1569
42.1569
[9] 240.1960 308.4310 42.1569 42.1569 42.1569 42.1569 42.1569
42.1569
[17] 42.1569 42.1569 42.1569 42.1569 279.8040 42.1569 42.1569
when I sort, it gave me the right order
sort(z)
[1] 42.1569 42.1569 42.1569 42.1569 42.1569 42.1569 42.1569
42.1569
[9] 42.1569 42.1569 42.1569 42.1569 42.1569 42.1569 42.1569
113.7250
[17] 140.7840 156.2750 183.1370 201.9610 240.1960 279.8040 308.4310
BUT when I use the order, the returned index is strange and not right.
You can check the first 4 values.
order (z)
[1] 6 7 8 11 12 13 14 15 16 17 18 19 20 22 23 3 4 5 1 2 9
21 10
I am not sure why R does not order it correctly when handling a vector
with repetitive values.
I use just the first 4 values of z, then it ordered correctly.
order (z[1:4])
[1] 3 4 1 2
Can someone help? What is the problem here? Is this a R bug? How to
order when handling a vector with repetitive values?
--
Waverley @ Palo Alto
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