Hi, This is not exactly the same, but there was a recent thread on rbind()ing dataframes from a list:
http://r.789695.n4.nabble.com/Please-explain-do-call-in-this-context-or-critique-to-stack-this-list-faster-td2526908.html Given that, I wonder if this would work for you: ll <- list(c("1","2","3"),c("2","3","4")) dd <- data.frame(matrix(nrow=10,ncol=3)) # rbind() each element of the list together into a data frame temp <- as.data.frame(do.call("rbind", ll), stringsAsFactors = FALSE) # assign that dataframe to whichever rows of dd you want dd[1:2, ] <- temp # print to screen dd Just a thought, Josh On Tue, Sep 7, 2010 at 11:17 PM, raje...@cse.iitm.ac.in <raje...@cse.iitm.ac.in> wrote: > > Hi, > > I have a preallocated dataframe to which I have to add a list whose vectors > will become rows in the dataframe. This is done iteratively. How can I do > this? > I'm dealing with very large numbers...list of 1000 vectors to a dataframe of > 200000 iteratively > > for e.g. > my list is as follows > > ll<-list(c("1","2","3"),c("2","3","4")) > > I have to add this to a dataframe > dd<-data.frame(matrix(nrow=10,ncol=3)) > > so that I get > 1 2 3 > 2 3 4 > etc. > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Joshua Wiley Ph.D. Student, Health Psychology University of California, Los Angeles http://www.joshuawiley.com/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
