Here's one possibility:
sort.v<-c(Lake=1,Shoreline=2,Floodplain=3)
test.df[order(sort.v[as.character(test.df$Zone)]),]
Zone Cover
2 Lake 60
3 Shoreline 70
1 Floodplain 50
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Thu, 26 Aug 2010, chipmaney wrote:
I have a dataset I need to sort:
test.df<-data.frame(Zone=c("Floodplain", "Lake",
"Shoreline"),Cover=c(50,60,70))
However, I don't want it sorted ascending/descending but in an order that I
define via a vector:
sort.v<-data.frame(c("Lake","Shoreline","Floodplain"))
I realize I could probably just create the vector of [factors] in the order
I want, then assign the value:
sort.v$Cover<-test.df$Cover
However, this is inefficient. Is there source code or a syntactical trick
that will do the same more efficiently? Note: I have investigated order()
and sort(), but neither seems to have an argument for defining the sorting
order.
Thanks in advance, Chipper
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