On Aug 26, 2010, at 2:35 PM, Le Wang wrote:

Thanks, David.

I did try to use predict() to obtain the graph,

"Try"? How? Code?

( predict() is used to obtain numbers, not to do graphing. )

but it somehow looks
different from the one generated by "plot" command.

I have no idea what you actually did. There is no plot method for predict objects.

So, I was
wondering if there is any way that I can get the one generated by
"plot" so that I can compare. Thank you.

And, .... what kind of model is "model", anyway? The only "plot.errors.method" argument with a value of "asymptotic" I could find went with package np. What does class(model) return?

I fear you have not have read the Posting Guide where it is carefully explained that one MUST reference packages being used, true? (I suppose I should have been alerted by the strange plot argument.)

There is no np.predict listed in help for package=np, but after loading package=np, I do see a predict method: predict.npregression*

So. Why don't you go the full Posting Guide route (and actually reading the Posting Guide) and include data and code?

--
David,

Le

On Wed, Aug 25, 2010 at 11:15 PM, David Winsemius
<dwinsem...@comcast.net> wrote:

On Aug 25, 2010, at 10:46 PM, Le Wang wrote:

Hi there,

I have a question regarding the "plot" command after estimation.

Specifically, I estimate a model, say regressing y on x and z. And
after estimation, I would like to plot the fitted values against x,
but I don't need that for z. The following command always gives two
graphs, for both variables x and z.

plot.np<-plot(model, plot.errors.method = "asymptotic")

My question is, what option should I specify in order to get the graph
for x only?

Pick a constant value for "z" and vary "x" in a dataframe that you offer to
the newdata argument of predict.

?predict

Then plot those values versus x.


I know this is probably a very simple question, but I searched around
for a while without any luck. Thank you for your time.

--

David Winsemius, MD
West Hartford, CT





--
~~~~~~~~~~~~~~~~~~~~~~
Le Wang, Ph.D
Population Center
University of Minnesota

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David Winsemius, MD
West Hartford, CT

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