I didn't follow the earlier replies, but since you still can't seem to get p-values, what about this: (I also couldn't run your sample code, so this is a toy example; and do you mean anova() - I'm not familiar with Anova(), and didn't see anything with ??Anova)
> x <- runif(100) > y <- runif(100) > xy.anova <- anova(lm(y ~ x)) > xy.anova Analysis of Variance Table Response: y Df Sum Sq Mean Sq F value Pr(>F) x 1 0.0001 0.000086 0.001 0.9745 Residuals 98 8.2018 0.083692 > names(xy.anova) [1] "Df" "Sum Sq" "Mean Sq" "F value" "Pr(>F)" > xy.anova$"Pr(>F)" [1] 0.9745443 NA Sarah On Mon, Aug 23, 2010 at 5:35 PM, Johan Steen <johan.st...@gmail.com> wrote: > Thanks for your replies, > > but unfortunately none of them seem to help. > I do get p-values in the output, but can't seem to locate them anywhere in > these objects via the str() function. I also get very different output using > str() than you obtained from the lm help page > -- Sarah Goslee http://www.functionaldiversity.org ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.