I remembered wrong, the problem rised int the next line to the mentioned one, z was wrong, and I didn't see way. But new day, new point of wiew. For anybody's interest here is the solution.
The original try was this: x <- seq(-1.95, 1.95, length = 30) y <- seq(-1.95, 1.95, length = 35) z <- as.matrix(read.table(file="mSample.dat")) # mSample.dat looks like this: " 104 107" (... 32l, 48c) ... (the same as in the example) ... persp(x, y, z, col=color[facetcol], phi=30, theta=-30) And it's wrong at the first three line. Now obviously, because z won't be a 30x35 matrix, but just az large as it's determined in the file. So I placed the first lines with this: z <- as.matrix(read.table(file="mSample.dat")) x <- seq(1, nrow(z)) y <- seq(1, ncol(z)) which is probably better in this case, because the z values are not calculated from x and y, so it's no point to determine their lenghts manually. -- View this message in context: http://r.789695.n4.nabble.com/using-color-palette-in-persp-tp2328464p2329451.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
