Hello,
I have question about the overhead in lapply.
x is a list of 3000 lists. Each of the i (1<=i<=3000) list elements is
pair of two elements: a string vector and a data frame
x is roughly 235MB.
> gc()
##
> z <- system.time(y <- lapply(x,function(r){
system.time(serialize(r,NULL))['elapsed']
}))
> sum(unlist(y))
18.812
> z
user system elapsed
494.144 0.041 494.247
So, the entire lapply takes ~26 times longer than the sum of the
individual operations.
Have i missed something?
Regards
Saptarshi
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