On Aug 4, 2010, at 9:46 AM, Leigh E. Lommen wrote:


I have the following array:

head(stocks)
DATE TICKER PERMNO EXCHCD TSYMBOL TRDSTAT SHROUT PRC RET

1 19950131   EWST  10001      3    EWST       A   2224 -7.75000
-0.031250
2 19950228   EWST  10001      3    EWST       A   2224  7.54688
-0.026210
3 19950331 EWST 10001 3 EWST A 2244 7.50000 0.00637
4 19950428   EWST  10001      3    EWST       A   2244  7.50000
0.000000
5 19950531   EWST  10001      3    EWST       A   2244 -7.87500
0.050000
6 19950630   EWST  10001      3    EWST       A   2254  8.25000
0.060317

I am trying to find stocks(TICKER) that are delisted at points (t-5) to
t(19950630) to (t+7) using the following code:

#find delistings or incomplete returns
for (i in 1:T)
        {
        if ( (stocks[i,1]==19950630)&
(stocks[i,2]!=stocks[i5,2])|(stocks[i,2]!=stocks[i+5,2]) )
                       ^
Missing operator?



                {
                print("Delisted stocks are: ")
                print(stocks[i,2])
                }
        }

But I get the following error message:

Error in if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i - :

 argument is of length zero
In addition: Warning messages:
1: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
 the condition has length > 1 and only the first element will be used
2: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
 the condition has length > 1 and only the first element will be used
3: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
 the condition has length > 1 and only the first element will be used
4: In if ((stocks[i, 1] == 19950630) & (stocks[i, 2] != stocks[i -  :
 the condition has length > 1 and only the first element will be used

Please help??

Regards,
Leigh

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David Winsemius, MD
West Hartford, CT

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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