On Jul 20, 2010, at 2:39 AM, Nita Umashankar wrote: > Hello, > I am getting some results from my Probit estimation in R that are in the > opposite direction of what I hypothesized. In sas, the default is > probability that y=0 (instead of 1) so one needs to type the word > "descending" to get P(y=1). Is the same true for R? Is the default set to > P(0)?
Why not just try it? > y <- c(1,0,0) > glm(y~1,binomial(probit)) Call: glm(formula = y ~ 1, family = binomial(probit)) Coefficients: (Intercept) -0.4307 Intercept is less than zero so it's probit(P(1))==qnorm(1/3). (BTW, I don't think "what SAS does" is a well-defined concept. There are three procedures that will do probit regression - fortunately PROC CATMOD will not... - and they each have more than one way of specifying the response variable.) > Thank you in advance. > > Nita Umashankar > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. -- Peter Dalgaard Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Email: pd....@cbs.dk Priv: pda...@gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.