On Jul 9, 2010, at 8:46 AM, Trafim Vanishek wrote:
> Dear all,
>
> might seem and easy question but I cannot figure it out.
>
> floor(100*(.58))
> [1] 57
>
> where is the trick here? And how can I end up with the right answer?
>
> Thanks a lot everybody for your help.
> Trafim
> sprintf("%.20f", 100 * .58)
[1] "57.99999999999999289457"
See R FAQ 7.31
HTH,
Marc Schwartz
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