I'm not sure your question completely makes sense, but perhaps this will
help:
set.seed(1)
d<- data.frame(matrix(floor(runif(100, max=10)), 10)) # Example data
d[apply(d == 9, 1, any), ] # Select rows with 9 in any column
## Or more generally:
d[ , c(1, 2, 3)] == c(2, 2, 9) # Or maybe d == 0:9 to select on
all columns
apply(d[ , c(1, 2, 3)] == c(2, 2, 9), 1, any) # any() being the general `|`
function here
d[apply(d[ ,c(1, 2, 3)] == c(2, 2, 9), 1, any), ] # Finally: the rows we were
looking for
A bit over-engineered, perhaps, but gets you to use some generally
useful functions.
Hope this helps.
Allan
On 06/07/10 09:33, Kunzler, Andreas wrote:
Dear list,
I'm looking for a way to select rows of a data.frame with changing number of
columns (constraint) involved.
Assume a data (d) structure like
Var.1 Var.2 Var.3
9 2 1
2 9 5
1 2 1
I know the number of involved columns.
Is there a way to generate the following selection automatically (maybe for
loop), so that it makes no difference if there are two or ten columns involved.
Selection:
d[d$Var.1==9 | d$Var.1==9 | d$Var.1==9 ,]
Does anybody know a way?
Thanks
Mit freundlichen Grüßen
Andreas Kunzler
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