Try this:
reshape(MyData, direction = 'long', varying = list(c('jan', 'feb')), idvar =
2:3)
On Tue, Jun 29, 2010 at 2:22 PM, Dimitri Liakhovitski <
dimitri.liakhovit...@gmail.com> wrote:
> Hello, everyone!
> I have a very simple task - I have a data frame (see MyData below) and
> I need to stack the data (see result below).
> I wrote the syntax below - it's very basic and it does what I need.
> But I am sure what I am trying to do is a very typical task and there
> must be a much shorter/more elegant way of doing it.
> Any advice?
>
> Thank you very much!
>
>
>
> MyData<-data.frame(names=c("John","Mary","Paul","Debby"),jan=c(10,15,20,25),feb=c(1,2,3,4))
> (MyData)
> months<-names(MyData)[-1]
> people<-as.character(MyData[[1]])
>
> ### Creating a temp matrix with people as columns and months as rows:
> transposed<-apply(MyData[-1],1,t)
>
> ### Putting vertical data (months as rows) - for each person - into a list:
> list.of.stacked<-list()
> for(i in 1:ncol(transposed)){
>
> list.of.stacked[[i]]<-as.data.frame(matrix(ncol=3,nrow=length(months)))
> names(list.of.stacked[[i]])<-c("month","values","person")
> list.of.stacked[[i]][["month"]]<-months
> list.of.stacked[[i]][["values"]]<-transposed[1:nrow(transposed),i]
> list.of.stacked[[i]][["person"]]<-people[i]
> }
> (list.of.stacked)
>
> ### Creating a data frame from the list:
> result<-do.call(rbind,list.of.stacked)
> (result)
>
>
> --
> Dimitri Liakhovitski
> Ninah Consulting
> www.ninah.com
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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