1) Create a table with two columns: payor and payor.group. 2) Merge that table with your original data
Hadley On Mon, Jun 28, 2010 at 10:46 AM, GL <pfl...@shands.ufl.edu> wrote: > > I'm guessing there's a more efficient way to do the following using the index > features of R. Appreciate any thoughts.... > > for (i in 1:nrow(dbs1)){ > if(dbs1$Payor[i] %in% Payor.Group.Medicaid) dbs1$Payor.Group[i] = > "Medicaid" > if(dbs1$Payor[i] %in% Payor.Group.Medicare) dbs1$Payor.Group[i] = > "Medicare" > if(dbs1$Payor[i] %in% Payor.Group.Commercial) dbs1$Payor.Group[i] = > "Commercial" > if(dbs1$Payor[i] %in% Payor.Group.Workers.Comp) dbs1$Payor.Group[i] = > "Workers Comp" > if(dbs1$Payor[i] %in% Payor.Group.Self.Pay) dbs1$Payor.Group[i] = "Self > Pay" > if(dbs1$Adm.Source[i] %in% Adm.Source.Group.Newborn) > dbs1$Adm.Source.Group[i] = "Newborn" > if(dbs1$Adm.Source[i] %in% Adm.Source.Group.ED) dbs1$Adm.Source.Group[i] > = "ED" > if(dbs1$Adm.Source[i] %in% Adm.Source.Group.Routine) > dbs1$Adm.Source.Group[i] = "Routine" > if(dbs1$Adm.Source[i] %in% Adm.Source.Group.Transfer) > dbs1$Adm.Source.Group[i] = "Transfer" > } > -- > View this message in context: > http://r.789695.n4.nabble.com/Basic-question-more-efficient-method-than-loop-tp2271096p2271096.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Assistant Professor / Dobelman Family Junior Chair Department of Statistics / Rice University http://had.co.nz/ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.