Here is an alternative:
> lst <- list(m = c('a','b','c'), n = c('c','a'), l = c('a','bc'))
> set <- c("a", "c")
> (w <- sapply(lst, function(x) all(set %in% x)))
m n l
TRUE TRUE FALSE
> names(w)[w]
[1] "m" "n"
-----Original Message-----
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Henrique Dallazuanna
Sent: Thursday, 24 June 2010 9:21 AM
To: Yuan Jian
Cc: r-help@r-project.org
Subject: Re: [R] list operation
Try this:
lst[colSums(mapply('%in%', list(set), lst)) == 2]
On Wed, Jun 23, 2010 at 10:35 AM, Yuan Jian <jayuan2...@yahoo.com> wrote:
> Hi,
>
> it seems a simple problem, but I can not find a clear way.
> I have a list:
> lst=list(m=c('a','b','c'),n=c('c','a'),l=c('a','bc'))
> > lst
> $m
> [1] "a" "b" "c"
> $n
> [1] "c" "a"
> $l
> [1] "a" "bc"
>
> how can I get list elements that include a given subset? for example, for
> given subset {'a','c'}, the answer should be 'm' and 'n'.
>
> thanks
> Yu
>
>
>
> [[alternative HTML version deleted]]
>
>
> ______________________________________________
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
[[alternative HTML version deleted]]
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