Yes, that's it. Thank you again!
Dimitris Rizopoulos wrote: > > do you mean the following?: > > out <- rowMeans(matrix(unlist(res), ncol = length(res))) > dim(out) <- dim(res[[1]]) > out > > > Best, > Dimitris > > ---- > Dimitris Rizopoulos > Ph.D. Student > Biostatistical Centre > School of Public Health > Catholic University of Leuven > > Address: Kapucijnenvoer 35, Leuven, Belgium > Tel: +32/(0)16/336899 > Fax: +32/(0)16/337015 > Web: http://med.kuleuven.be/biostat/ > http://www.student.kuleuven.be/~m0390867/dimitris.htm > > > Quoting dxc13 <[EMAIL PROTECTED]>: > >> >> useR's, >> >> This is a follow up question to one I previously asked. Consider the >> 3-element list below >> >>> res >> [[1]] >> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] >> [,12] >> [,13] [,14] >> [1,] NA NA NA 1.25 0.25 0.75 NA NA NA NA NA NA 1.25 >> 0.25 >> [2,] 1.25 0.25 0.75 NA NA NA NA NA NA 1.25 0.25 0.75 NA >> NA >> [3,] NA NA NA NA NA NA 1.25 0.25 0.75 NA NA NA NA >> NA >> [4,] NA NA 1.25 0.25 0.75 NA NA NA NA NA NA 1.25 0.25 >> 0.75 >> [5,] NA NA NA NA NA 1.25 0.25 0.75 NA NA NA NA NA >> NA >> >> [[2]] >> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] >> [,13] [,14] >> [1,] NA NA NA NA NA NA NA NA NA NA NA NA NA >> 1.25 >> [2,] 1.25 NA NA NA NA NA NA NA NA NA NA NA NA >> NA >> [3,] 1.25 1.25 1.25 1.25 1.25 1.25 1.25 1.25 1.25 0.25 0.25 0.25 0.25 >> 0.25 >> [4,] NA NA NA NA NA NA NA NA NA NA NA NA NA >> NA >> [5,] NA NA NA NA NA 1.25 NA NA NA NA NA NA >> NA >> NA >> >> [[3]] >> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] >> [,13] [,14] >> [1,] NA NA NA NA NA NA NA NA NA NA NA NA NA >> 1.25 >> [2,] 0.25 NA NA NA NA NA NA NA NA NA NA NA NA >> NA >> [3,] 1.25 1.25 1.25 1.25 1.25 1.25 1.25 1.25 1.25 0.25 0.25 0.25 0.25 >> 0.25 >> [4,] NA NA NA NA NA NA NA NA NA NA NA NA NA >> NA >> [5,] NA NA NA NA NA 0.25 NA NA NA NA NA NA >> NA >> NA >> >> What I want to do is find the values that are not NA simultaneously for >> each >> value in each element of the list, and then average these numbers and >> store >> them in a 14x1 vector. For example, in position (2,1) in each of the 3 >> elements of the res list, there is a value, 1.25 in [[1]] and [[2]], 0.25 >> in >> [[3]]. Since there is a value in this position in all elements of the >> list >> I want to average these numbers: (1.25+1.25+0.25)/3 and store this value >> in >> a numeric vector. So, if there are not 3 values to average, this means >> that a given position (i,j) does not have a value in each element of the >> list and thus I want to store NA in the 14x1 vector. In the end, the >> 14x1 >> vector will be mixed with values and NA's or NaN's. >> >> Does anyone know a efficient way to do this? Maybe using mapply()? I >> hope >> it is clear. Thank you for any input. >> >> Derek >> -- >> View this message in context: >> http://www.nabble.com/using-mapply%28%29-tp14697351p14697351.html >> Sent from the R help mailing list archive at Nabble.com. >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> >> > > > > Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > -- View this message in context: http://www.nabble.com/using-mapply%28%29-tp14697351p14698238.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
