Thanks Gabor!! On 1/6/08, Gabor Grothendieck <[EMAIL PROTECTED]> wrote: > > On Jan 6, 2008 5:17 PM, tom soyer <[EMAIL PROTECTED]> wrote: > > Hi, > > > > I have a ts object with a frequency of 4, i.e., quarterly data, and I > would > > like to calculate the mean for each quarter. So for example: > > > > > ts.data=ts(1:20,start=c(1984,2),frequency=4) > > > ts.data > > Qtr1 Qtr2 Qtr3 Qtr4 > > 1984 1 2 3 > > 1985 4 5 6 7 > > 1986 8 9 10 11 > > 1987 12 13 14 15 > > 1988 16 17 18 19 > > 1989 20 > > > > If I do this manually, the mean for the 1st quarter would be > > mean(c(4,8,12,16,20)), which is 12. But I am wondering if there is a R > > function that could do this faster. I tried aggregate.ts but it didn't > work: > > > > > aggregate(ts.data,nfrequency=4,mean) > > Qtr1 Qtr2 Qtr3 Qtr4 > > 1984 1 2 3 > > 1985 4 5 6 7 > > 1986 8 9 10 11 > > 1987 12 13 14 15 > > 1988 16 17 18 19 > > 1989 20 > > > > Does anyone know what am I doing wrong? > > aggregate.ts aggregates to produce series of coarser granularity > which is not what you want. You want the ordinary aggregate: > > aggregate(c(ts.data), list(qtr = cycle(ts.data)), mean) > > # or tapply: > > tapply(ts.data, cycle(ts.data), mean) > > See ?aggregate >
-- Tom [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.