oops, it should be: rms=(sum((x-mean(x))^2)/(length(x)-1))^(1/2)

On 1/3/08, tom soyer <[EMAIL PROTECTED]> wrote:
>
> Thanks Jim. Yes it does... but I calculated the root mean square (rms),
> and couldn't reproduce the result without multiplying the rms by 2. I don't
> know why...
>
>  > x=c(2,4,3,4,5)
> > mean(x)
> [1] 3.6
> > x-mean(x)
> [1] -1.6  0.4 -0.6  0.4  1.4
> > scale(x)
>            [,1]
> [1,] -1.4032928
> [2,]  0.3508232
> [3,] -0.5262348
> [4,]  0.3508232
> [5,]  1.2278812
> attr(,"scaled:center")
> [1] 3.6
> attr(,"scaled:scale")
> [1] 1.140175
> > rms=sum((x-mean(x))^2)^(1/2)/(length(x)-1)
> > rms
> [1] 0.5700877
> > (x-mean(x))/rms
> [1] -2.8065857  0.7016464 -1.0524696  0.7016464  2.4557625
> > (x-mean(x))/(rms*2)
> [1] -1.4032928  0.3508232 -0.5262348  0.3508232  1.2278812
>
>
>  On 1/3/08, jim holtman <[EMAIL PROTECTED]> wrote:
> >
> > Does this give you what you want?
> >
> > > x=c(2,4,3,4,5)
> > > ?scale
> > > scale(x,scale=FALSE)
> >     [,1]
> > [1,] -1.6
> > [2,]  0.4
> > [3,] -0.6
> > [4,]  0.4
> > [5,]  1.4
> > attr(,"scaled:center")
> > [1] 3.6
> > >
> >
> > Default is to performance scaling: "If scale is TRUE then scaling is
> > done by dividing the (centered) columns of x by their
> > root-mean-square, and if scale is FALSE, no scaling is done. "
> >
> > On Jan 3, 2008 9:37 PM, tom soyer <[EMAIL PROTECTED]> wrote:
> > > Hi,
> > >
> > > The documentation for scale() states:"If center is TRUE then centering
> > is
> > > done by subtracting the column means (omitting NAs) of x from their
> > > corresponding columns". But it seems that R is subtracting something
> > else
> > > instead of the column mean:
> > >
> > > > x=c(2,4,3,4,5)
> > > > mean(x)
> > > [1] 3.6
> > > > x-mean(x)
> > > [1] -1.6  0.4 -0.6  0.4  1.4
> > > > scale(x)
> > >           [,1]
> > > [1,] -1.4032928
> > > [2,]  0.3508232
> > > [3,] -0.5262348
> > > [4,]   0.3508232
> > > [5,]  1.2278812
> > > attr(,"scaled:center")
> > > [1] 3.6
> > > attr(,"scaled:scale")
> > > [1] 1.140175
> > >
> > > Notice that -1.4 is not the same as -1.6, and 1.2 is not the same as
> > 1.4,
> > > etc. Does anyone know what exactly is scale() doing if it is not
> > subtracting
> > > the column mean? Thanks.
> > >
> > > --
> > > Tom
> > >
> > >        [[alternative HTML version deleted]]
> > >
> > > ______________________________________________
> > > R-help@r-project.org mailing list
> > > https://stat.ethz.ch/mailman/listinfo/r-help
> > > PLEASE do read the posting guide
> > http://www.R-project.org/posting-guide.html<http://www.r-project.org/posting-guide.html>
> > > and provide commented, minimal, self-contained, reproducible code.
> > >
> >
> >
> >
> > --
> > Jim Holtman
> > Cincinnati, OH
> > +1 513 646 9390
> >
> > What is the problem you are trying to solve?
> >
>
>
>
> --
> Tom




-- 
Tom

        [[alternative HTML version deleted]]

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