i didn't test, but i think you want something like:
table(apply(x, 1, paste, collapse=","))
where "x" is your matrix...
b
On Dec 23, 2007, at 5:01 AM, Jim Lemon wrote:
Louis Martin wrote:
Hi,
I have a matrix of duplicate rows. How to output a list the unique
rows with their count? I have used "unique" to have the unique
rows, but can't produce the occurences of each unique row.
Hi Louis,
If you want the unique rows returned, this might do the job.
unique.rows<-function(x) {
nrows<-dim(x)[1]
urows<-1:nrows
for(i in 1:(nrows-1)) {
for(j in (i+1):nrows) {
if(!is.na(urows[j])) if(all(x[i,]==x[j,])) urows[j]<-NA
}
}
return(x[urows[!is.na(urows)],])
}
Jim
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