try this:
> dates <- c("January 12, 1988", "March 4, 2006", "1958")
> gsub(".*, *(.*)", "\\1", dates) # notice the it is comma blank asterisk in
> the string
[1] "1988" "2006" "1958"
On Dec 16, 2007 7:34 AM, Anupa Fabian <[EMAIL PROTECTED]> wrote:
> I have some data whose date column consists of two types of date entries:
> (a) year-only entries (eg "1983") and
> (b) full date info (eg September 12, 1962).
>
> Here's what the non-standard date info looks like:
> > mode(non.standard.dates)
> [1] "numeric"
> > head(non.standard.dates)
> [1] July 15, 1925 February 13, 1923 July 10, 1988 February 24, 1931
> [5] 1952 January 9, 1957
> 1638 Levels: 1732 1735 1736 1740 1745 1748 1749 1750 1752 1754 1757 1760 ...
> September 9, 1898
>
> I just want to extract out the year information (viz in the example above:
> 1925, 1923, 1988, 1931, 1952 and 1957) and create a "year" column. Have tried
> using the R date libraries without success, but they seem more designed for
> working with dates which are standardized the same way.... I'd really
> appreciate suggestions from more experienced R folks. Thank you.
>
>
>
>
>
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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
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