I am not sure to understand your problem, but it seems to me that you can use directly the function on the range of the dates:
> x=as.Date(c('2007-01-01','2007-01-02')) > fff=function(x){y=x+1;return(y)} > fff(x) [1] "2007-01-02" "2007-01-03" > class(fff(x)) [1] "Date" Perhaps your function use a different input (not a vector of dates but a dataframe)? domenico vistocco Ranjan Bagchi wrote: > On Wed, 5 Dec 2007, Prof Brian Ripley wrote: > >> [...] >> > > Thanks I'll read it more carefully. > > >> Perhaps if you told us what you are trying to achieve we might be able to >> help you achieve it. >> >> > > I have a function which takes a date as an argument. I've tested it, and > I'd like to run it over a range of dates. So I'm looking at apply- or > map- type functions. > > >> -- >> Brian D. Ripley, [EMAIL PROTECTED] >> Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ >> University of Oxford, Tel: +44 1865 272861 (self) >> 1 South Parks Road, +44 1865 272866 (PA) >> Oxford OX1 3TG, UK Fax: +44 1865 272595 >> >> >> >> > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.