say your array is called "no.named.array".
then:
no.named.array[no.named.array == 0] <- NA
rowMeans(no.named.array, dims=2, na.rm=T)
b
On Dec 3, 2007, at 7:24 PM, threshold wrote:
Hi, I deal with 3D array say:
, , 1
[,1] [,2] [,3] [,4] [,5]
[1,] 1 4 7 10 13
[2,] 2 5 8 11 14
[3,] 3 6 9 12 15
, , 2
[,1] [,2] [,3] [,4] [,5]
[1,] 16 19 22 25 28
[2,] 17 20 23 26 29
[3,] 18 21 24 27 30
, , 3
[,1] [,2] [,3] [,4] [,5]
[1,] 31 34 37 40 43
[2,] 32 35 38 41 44
[3,] 33 36 39 42 45
I want to calculate means in the cells with respect to dimention 3rd
so for
example (1+16+31)/3 or (15+30+45)/3 AND avoid taking zeros into
account.
I did it with a loop but I guess there is the other more
straightforward
method. will be very grateful for help...
best, rob
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