I have this maximum liklihood estimate problem i need to find the roots of the following:
[sum (from i=1 to n) ] ((2(x[i]-parameter)/(1+(x[i]-parameter)^2))=0 given to me is the x vector which has length 100 how would I find the roots using R? I have 2 thoughts...... 1 is using a grid search ... eg. brute force, just choosing a whole bunch of different values for my parameter .... such as parameter=seq(0,100,.1) .... and this is what I have so far, john=rep(0,length(x)) for(i in 1:length(x)) { john[i]=((x[i]-0)/(1+(x[i]-0)^2)) } sum(john) then john=rep(0,length(x)) for(i in 1:length(x)) { john[i]=((x[i]-.1)/(1+(x[i]-.1)^2)) } sum(john) then john=rep(0,length(x)) for(i in 1:length(x)) { john[i]=((x[i]-.2)/(1+(x[i]-.2)^2)) } sum(john) something like this ... theta=seq(0,100,.1) john=rep(0,length(x)) for(i in 1:length(x)) { john[i]=((x[i]-theta[j])/(1+(x[i]-theta[j])^2)) } sum(john) but something is wrong with my code because its not working. Anyone have any ideas? (I am very new to R and statistical software in general) The 2nd thought was to use the Newton Raphson Method, but, I dont even know where to start with that. Any thoughts help. Thanks -- View this message in context: http://www.nabble.com/finding-roots-%28Max-Like-Est%29-tf4901659.html#a14040895 Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.