Not the most efficient way would be to use a loop.... If x is your rel object, you can do the following:
for (i in 1:length(x$values)) { cat("(",x$values[i],",",x$lengths[i],") ") if (i %% 10 == 0) cat("\n") } cat("\n") --- Alexy Khrabrov <[EMAIL PROTECTED]> wrote: > I'm running rle() on a long vector, and get a result > which looks like > > > uc > Run Length Encoding > lengths: int [1:16753] 1 1 1 1 1 1 1 1 1 1 ... > values : int [1:16753] 29462748 22596107 18322820 > 14323315 > 12684505 9909036 7296916 6857692 5884755 5883697 ... > > > I can print uc$names or uc$levels separately. Is > there any way to > print them together as tuples, looking like > > (29462748, 1) (22596107, 1) ... > (5883697, 1) ... > ... > > Cheers, > Alexy > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, > reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.