Thanks for your reply. I have tried the reproducible example you have provided (thanks!) in 3 different versions of R, and get what you get in R version 2.5.1, but in 2.3.1 (which I normally use) and 2.1.0 (which I still have installed) I get factors. I guess this means I should switch to the new version?
Christian Prof Brian Ripley wrote: > I am trying to build a data.frame from some vectors and some matrices > and seem to be unable to find out how to do this without converting > everything to factors. > I can prevent conversion of the vectors by using I(), as explained in > help(data.frame). However, this doesn't help with the matrices: if I try > I() with the matrix, the matrix gets incorporated into the data frame as > a whole, rather than as a list of vectors as it should be. ("as.is=T" > doesn't help either, and neither does "options(stringsAsFactors = FALSE)".) > > I think we need the reproducible example we asked for. I get > >> z <- matrix(letters[1:12], 4, 3) >> z2 <- data.frame(x=1:4, z=z, stringsAsFactors=FALSE) >> sapply(z2, class) > x z.1 z.2 z.3 > "integer" "character" "character" "character" > > so it is working as documented. (BTW, using I() on a matrix is intended > to insert a matrix as a single entity, and as.is is not an argument to > data.frame.) > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.