You can apply 1:n to order(x) so you don't wind up
subscripting x by every element in order(x).
o <- head(order(x), n) # positions
x[o]
A completely different approach, if X is a data frame with d as a data
column is this where the row names give the positions (don't know
about speed):
> library(sqldf)
> n <- 3
> X <- data.frame(d = c(5, 4, 6, 3, 10, 1, 12, 2))
> sqldf(paste("select * from X order by d limit", n), row.names = TRUE)
d
6 1
8 2
4 3
On Nov 11, 2007 6:43 PM, David Katz <[EMAIL PROTECTED]> wrote:
>
> What is the most efficient alternative to x[order(x)][1:n] where
> length(x)>>n?
> I also need the positions of the mins/maxs perhaps by preserving names.
>
> Thanks for any suggestions.
> --
> View this message in context:
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>
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