Try this: my.mat[my.mat > 0] <- table(my.mat)[-1][my.mat]
On Nov 10, 2007 8:19 AM, Milton Cezar Ribeiro <[EMAIL PROTECTED]> wrote: > Hi R-gurus, > > I have a matrix which looks like > > 00000000000 > 01110000220 > 01110000220 > 01110000000 > 00000000000 > > As you can see we have non-zero levels 1 and 2. I would like to fill an other > matrix with the frequency of non-zero levels in each cell. The results that I > need is > > 00000000000 > 09990000440 > 09990000440 > 09990000000 > 00000000000 > > If I run the script below I can simulate the first matrix and count the cells > for each non-zero levels. My question is how can I fill the second matrix in > a easy way. > > my.mat<-matrix( > c(0,0,0,0,0,0,0,0,0,0,0, > 0,1,1,1,0,0,0,0,2,2,0, > 0,1,1,1,0,0,0,0,2,2,0, > 0,1,1,1,0,0,0,0,0,0,0, > 0,0,0,0,0,0,0,0,0,0,0),nrow=5,byrow=T) > my.mat.freq<-data.frame(table(my.mat)) > my.mat.freq<-subset(my.mat.freq,my.mat.freq$my.mat!=0) > my.mat.freq > > > Any idea? > > Kind regards > > Miltinho > > > > para armazenamento! > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
