On 10/31/2007 8:06 AM, livia wrote: > Hello, > > I would like to use the cbind() function to construct a matrix used in the > middle of a function as following > > for (i in 1:1000) { > b[i] <- function(cbind(a[[1]][[i]], > a[[2]][[i]],a[[3]][[i]],...a[[67]][[i]])) > } > > > Is there an easy way of achieving this rather than "cbind" every column?
What you're doing is a little complicated (taking the i'th element out of elements 1:67 in a list), so the solution is bound to be a little complicated too. But something like this will save you typing: # construct a list of the i'th elements ithelements <- lapply(a[1:67], function(e) e[[i]]) # pass them as args to cbind do.call(cbind, ithelements) I haven't tested this (not having your data at hand), but if it doesn't work, something like it should. Duncan Murdoch ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.