List,
I am attempting to take a row of data from one matrix to another if it
satisfies a certain condition. When R puts the data in the new matrix it is
changing the characters to integers and giving them values which aren't very
helpful to my analysis. I would use as.character, but I need to keep the
double values as is. Is there a way to copy the entry exactly as is to the new
matrix, without having to use a separate statement for each entry. I've
included some code below. In my example all but row 5 are factors and should
be kept as characters, and column 7 has 2 levels, 1 or 2. Column 5, the
response is a double. Thanks for the help.
l = nrow(data)
n = 1
k = 1
data1trip = as.data.frame(rbind(1:7))
data2trip = as.data.frame(rbind(1:7))
colnames(data1trip) =...#my column names for data1trip
colnames(data2trip) =...# "" "" data2trip
for(i in 1:l){
if (data[i,7]=="1"){
data1trip[k,] = data[i,]; k=k+1 }
else {
data2trip[n,] = data[i,]; n = n+1}
}
is the only other way to do what i want....
for(i in 1:l){
if (data[i,7]=="1"){
data1trip[k,1] = as.char(data[i,1]
data1trip[k,2] = as.char(data[i,2]
data1trip[k,3] = data[i,]
.......
else {
and the same for those which have a "2" value in data[i,7]?
}
This second way seems a bit sloppy and i wanted to check if there existed a
more "professional" way to do it.
Thanks again,
Dave Mitchell
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