You got at least two answers on this yesterday. If you want more precise
answers, please tell us what your expected result is.
Uwe Ligges
osita k ezeh wrote:
> hello,
>
> please can anyone help me out. Am a new user of R
> program. Am having problem
> with this code below, not getting the expected
> results.
>
> Each m, the cumulative sum should be 1.000 but the
> 2nd and 3rd m returned 2.000 and 3.000
> instead of 1.000.
>
>
>
> thanks
> Aruike
>
>
>
> pp=function(x,n,M){z=1.0;a=2.3071430;b=7.266064;H=3
>
> out.h=c()
>
> out.y=c()
>
> out.m=c()
>
> out.prob=c()
>
>
>
> for(h in 1:H){
>
> for(m in 1:M){
>
> for(y in 0:m){
>
>
>
>
> g=lgamma(m+z)+lgamma(n[h]+a+b)+lgamma(x[h]+y+a)+lgamma(n[h]+m+b-x[h]-y)
>
>
>
> g=g-lgamma(y+z)-lgamma(m-y+z)-lgamma(x[h]+a)-lgamma(n[h]+b-x[h])-
> lgamma(n[h]+m+a+b)
>
>
>
> out.h=c(out.h,h)
>
> out.y=c(out.y,y)
>
> out.m=c(out.m,m)
>
> out.prob=c(out.prob, exp(g))
>
> out.cum=c(cumsum(out.prob))
>
>
>
> Result=data.frame(out.h,out.y,out.m,out.prob,out.cum)
>
> }}}}
>
> Kings=pp(x=c(19,20), n=c(52,60),3)
>
> Kings
>
> out.h out.y out.m out.prob out.cum
>
> 1 1 0 1 0.65395431 0.6539543
>
> 2 1 1 1 0.34604569 1.0000000
>
> 3 1 0 2 0.43127277 1.4312728
>
> 4 1 1 2 0.44536308 1.8766358
>
> 5 1 2 2 0.12336415 2.0000000
>
> 6 1 0 3 0.28672775 2.2867277
>
> 7 1 1 3 0.43363507 2.7203628
>
> 8 1 2 3 0.23440955 2.9547724
>
> 9 1 3 3 0.04522764 3.0000000
>
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> and provide commented, minimal, self-contained, reproducible code.
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
