On 10/5/07, Leeds, Mark (IED) <[EMAIL PROTECTED]> wrote:
> x[is.na(x)]<- y[is.na(x)] but this will only work correctly if x and y
> are the same length so I hope that is
> what you mean by the same style.


That can be fixed if y is at least as long as to reach the last NA
in x like this:

x[is.na(x)] <- y[which(is.na(x))]

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