Yes. I'm not yet facile with "|>", but I'm learning.
Spencer Graves
There's very little to know. This:
x |> f() |> g()
is just a different way of writing
g(f(x))
If f() or g() have extra arguments, just add them afterwards:
x |> f(a = 1) |> g(b = 2)
is just
g(f(x, a = 1), b = 2)
This isn't quite true of the magrittr pipe, but it is exactly true of
the base pipe.
Duncan Murdoch
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