Interestingly,
as.list(substitute(...()))
also works.
On Sun, Aug 12, 2018 at 1:16 PM, Duncan Murdoch
<murdoch.dun...@gmail.com> wrote:
> On 12/08/2018 4:00 PM, Henrik Bengtsson wrote:
>>
>> Hi. For any number of *known* arguments, we can do:
>>
>> one <- function(a) list(a = substitute(a))
>> two <- function(a, b) list(a = substitute(a), b = substitute(b))
>>
>> and so on. But how do I achieve the same when I have:
>>
>> dots <- function(...) list(???)
>>
>> I want to implement this such that I can do:
>>
>>> exprs <- dots(1+2)
>>> str(exprs)
>>
>> List of 1
>> $ : language 1 + 2
>>
>> as well as:
>>
>>> exprs <- dots(1+2, "a", rnorm(3))
>>> str(exprs)
>>
>> List of 3
>> $ : language 1 + 2
>> $ : chr "a"
>> $ : language rnorm(3)
>>
>> Is this possible to achieve using plain R code?
>
>
> I think so. substitute(list(...)) gives you a single expression containing
> a call to list() with the unevaluated arguments; you can convert that to
> what you want using something like
>
> dots <- function (...) {
> exprs <- substitute(list(...))
> as.list(exprs[-1])
> }
>
> Duncan Murdoch
>
>
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