Hi, base::mean is not consistent in terms of handling NA/NaN. Mean should not depend on order of its arguments while currently it is.
mean(c(NA, NaN)) #[1] NA mean(c(NaN, NA)) #[1] NaN I created issue so in case of no replies here status of it can be looked up at: https://bugs.r-project.org/bugzilla/show_bug.cgi?id=17441 Best, Jan [[alternative HTML version deleted]] ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel