Hi, base::mean is not consistent in terms of handling NA/NaN. Mean should not depend on order of its arguments while currently it is.
mean(c(NA, NaN))
#[1] NA
mean(c(NaN, NA))
#[1] NaN
I created issue so in case of no replies here status of it can be looked up
at:
https://bugs.r-project.org/bugzilla/show_bug.cgi?id=17441
Best,
Jan
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