Here is an attached patch.
Best,
Serguei.
Le 29/05/2017 à 12:21, Serguei Sokol a écrit :
The problem or actual R implementation relies on an assumption
that median(x[i] | x[i] <= quantile(x, 1/3)) == quantile(x, 1/6)
which reveals not to be true despite very trustful appearance.
If we continue with the example of x=y=1:9
then quantile(x, 1/6)=2.5 (here quantile() is taken in C-code sens, not R's one)
while median(y[i] | x[i] <= quantile(x, 1/3))=2
On the other sample's side we've got 7.5 and 8 for x and y respectively.
Hence the slope (8-2)/(7.5-2.5)=1.2
To get a correct version of this, one should calculate x robust points in the
same way as the y's,
i.e. xb=median(x[i] | x[i] <= quantile(x, 1/3)) and xt=median(x[i] | x[i] >=
quantile(x, 2/3))
Best,
Serguei.
Le 29/05/2017 à 10:02, peter dalgaard a écrit :
A usually trustworthy R correspondent posted a pure R implementation on SO at
some point in his lost youth:
https://stackoverflow.com/questions/3224731/john-tukey-median-median-or-resistant-line-statistical-test-for-r-and-line
This one does indeed generate the line of identity for the (1:9, 1:9) case, so
I do suspect that we have a genuine scr*wup in line().
Notice, incidentally, that
line(1:9+rnorm(9,,1e-1),1:9+rnorm(9,,1e-1))
Call:
line(1:9 + rnorm(9, , 0.1), 1:9 + rnorm(9, , 0.1))
Coefficients:
[1] -0.9407 1.1948
I.e., it is not likely an issue with exact integers or perfect fit.
-pd
On 29 May 2017, at 07:21 , GlenB <glnbr...@gmail.com> wrote:
Tukey divides the points into three groups, not the x and y values
separately.
I'll try to get hold of the book for a direct quote, might take a couple
of days.
Ah well, I can't get it for a week. But the fact that it's often called
Tukey's three group line (try a search on *tukey three group line* and
you'll get plenty of hits) is pretty much a giveaway.
On Mon, May 29, 2017 at 2:19 PM, GlenB <glnbr...@gmail.com> wrote:
Tukey divides the points into three groups, not the x and y values
separately.
I'll try to get hold of the book for a direct quote, might take a couple
of days.
On Mon, May 29, 2017 at 8:40 AM, Duncan Murdoch <murdoch.dun...@gmail.com>
wrote:
On 27/05/2017 9:28 PM, GlenB wrote:
Bug: stats::line() does not produce correct Tukey line when n mod 6 is 2
or
3
Example: line(1:9,1:9) should have intercept 0 and slope 1 but it gives
intercept -1 and slope 1.2
Trying line(1:i,1:i) across a range of i makes it clear there's a cycle
of
length 6, with four of every six correct.
Bug has been present across many versions.
The machine I just tried it on just now has R3.2.3:
If you look at the source (in src/library/stats/src/line.c), the
explanation is clear: the x value is chosen as the 1/6 quantile (according
to a particular definition of quantile), and the y value is chosen as the
median of the y values where x is less than or equal to the 1/3 quantile.
Those are different definitions (though I think they would be
asymptotically equivalent under pretty weak assumptions), so it's not
surprising the x value doesn't correspond perfectly to the y value, and the
line ends up "wrong".
So is it a bug? Well, that depends on Tukey's definition. I don't have
a copy of his book handy so I can't really say. Maybe the R function is
doing exactly what Tukey said it should, and that's not a bug. Or maybe R
is wrong.
Duncan Murdoch
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Serguei Sokol
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Metabolisme Integre et Dynamique des Systemes Metaboliques (MetaSys)
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--- line.c.orig 2016-03-17 00:03:03.000000000 +0100
+++ line.c 2017-05-29 15:06:55.727508967 +0200
@@ -25,8 +25,8 @@
/* Speed up by `inlining' these (as macros) [since R version 1.2] : */
#if 1
-#define il(n,x) (int)floor((n - 1) * x)
-#define iu(n,x) (int) ceil((n - 1) * x)
+#define il(n,x) (int)floor(((n) - 1) * (x))
+#define iu(n,x) (int) ceil(((n) - 1) * (x))
#else
static int il(int n, double x)
@@ -50,53 +50,53 @@
double slope, yint;
for(i = 0 ; i < n ; i++) {
- z[i] = x[i];
- w[i] = y[i];
+ z[i] = x[i];
+ w[i] = y[i];
}
R_rsort(z, n);/* z = ordered abscissae */
- tmp1 = z[il(n, 1./6.)];
- tmp2 = z[iu(n, 1./6.)]; xb = 0.5*(tmp1+tmp2);
-
tmp1 = z[il(n, 2./6.)];
- tmp2 = z[iu(n, 2./6.)]; x1 = 0.5*(tmp1+tmp2);
+ k = iu(n, 2./6.);
+ tmp2 = z[k]; x1 = 0.5*(tmp1+tmp2);
tmp1 = z[il(n, 4./6.)];
tmp2 = z[iu(n, 4./6.)]; x2 = 0.5*(tmp1+tmp2);
- tmp1 = z[il(n, 5./6.)];
- tmp2 = z[iu(n, 5./6.)]; xt = 0.5*(tmp1+tmp2);
-
slope = 0.;
for(j = 1 ; j <= 1 ; j++) {
- /* yb := Median(y[i]; x[i] <= quantile(x, 1/3) */
- k = 0;
- for(i = 0 ; i < n ; i++)
- if(x[i] <= x1)
- z[k++] = w[i];
- R_rsort(z, k);
- yb = 0.5 * (z[il(k, 0.5)] + z[iu(k, 0.5)]);
-
- /* yt := Median(y[i]; x[i] >= quantile(x, 2/3) */
- k = 0;
- for(i = 0 ; i < n ; i++)
- if(x[i] >= x2)
- z[k++] = w[i];
- R_rsort(z,k);
- yt = 0.5 * (z[il(k, 0.5)] + z[iu(k, 0.5)]);
-
- slope += (yt - yb)/(xt - xb);
- for(i = 0 ; i < n ; i++) {
- z[i] = y[i] - slope*x[i];
- /* never used: w[i] = z[i]; */
- }
- R_rsort(z,n);
- yint = 0.5 * (z[il(n, 0.5)] + z[iu(n, 0.5)]);
+ /* xb := Median(x[i]; x[i] <= quantile(x, 1/3) */
+ k += z[k] == x1;
+ xb = 0.5*(z[il(k, 0.5)] + z[iu(k, 0.5)]);
+ /* yb := Median(y[i]; x[i] <= quantile(x, 1/3) */
+ k = 0;
+ for(i = 0 ; i < n ; i++)
+ if(x[i] <= x1)
+ z[k++] = w[i];
+ R_rsort(z, k);
+ yb = 0.5 * (z[il(k, 0.5)] + z[iu(k, 0.5)]);
+
+ /* yt := Median(y[i]; x[i] >= quantile(x, 2/3) */
+ k = 0;
+ for(i = 0 ; i < n ; i++)
+ if(x[i] >= x2)
+ z[k++] = w[i];
+ R_rsort(z,k);
+ yt = 0.5 * (z[il(k, 0.5)] + z[iu(k, 0.5)]);
+ /* xt := Median(x[i]; x[i] >= quantile(x, 2/3) */
+ xt = 0.5 * (z[n - k + il(k, 0.5)] + z[n - k + iu(k, 0.5)]);
+
+ slope += (yt - yb)/(xt - xb);
+ for(i = 0 ; i < n ; i++) {
+ z[i] = y[i] - slope*x[i];
+ /* never used: w[i] = z[i]; */
+ }
+ R_rsort(z,n);
+ yint = 0.5 * (z[il(n, 0.5)] + z[iu(n, 0.5)]);
}
for( i = 0 ; i < n ; i++ ) {
- w[i] = yint + slope*x[i];
- z[i] = y[i] - w[i];
+ w[i] = yint + slope*x[i];
+ z[i] = y[i] - w[i];
}
coef[0] = yint;
coef[1] = slope;
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