hi simon
thank you for your questions ---- answers here:
I won't answer your question directly but some suggestions:
> a) does adding PACKAGE="ANTsR" to .Call change anything? (It should really
> be there if you are using strings as names)
>
this does change things .... for instance, this works:
library(ANTsR)
filename<-getANTsRData('r16')
.Call("antsImageRead", filename,'double',2) # Succeeds!
.Call("antsImageRead", filename,'double',2,PACKAGE=ANTsR) # Fails!
# Error in .Call("antsImageRead", filename, "double", 2, PACKAGE = "ANTsR")
:
# "antsImageRead" not available for .Call() for package "ANTsR"
the problem is when we call this function:
antsImageRead <- function( filename , dimension , pixeltype = "float" )
{
rval <- (.Call("antsImageRead", filename, pixeltype, dimension))
return(rval)
}
the we get the error antsImageRead not resolved from current namespace ,
e.g.:
> antsImageRead(filename,2)
Error in .Call("antsImageRead", filename, pixeltype, dimension) :
"antsImageRead" not resolved from current namespace (ANTsR)
>
b) you may want to consider use the more efficient registration - either
> explicit or in NAMESPACE - so in your case you could use
> NAMESPACE: useDynLib(ANTsR, antsImageRead, ...)
> foo.R: .Call(antsImageRead, ...)
>
yes - we have all of our shared libraries registered in the NAMESPACE file
e.g.
useDynLib(libRantsImageRead)
etcetera ....
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