Ben,
did you actually look at the result of your function with useRaster=TRUE ? ;)
[Hint: don't use an image that is symmetric]
Apart from that nice bug there are more issues as well, try
image(matrix(1:4,2),col=1:3)
The underlying issue is that as.raster() is not quite what you would hope.
Unfortunately I'm not aware of an easy fix (that doesn't involve going back to
RGB decomposition).
In general, I think it's a nice option, but I don't think you'll get away with
only a few lines...
Cheers,
Simon
On Feb 8, 2011, at 8:49 PM, Ben Bolker wrote:
>
> Has anyone yet tried incorporating rasterImage into the base image()
> function? It seems to make a *huge* difference, with
> a very small number of added/changed lines of code. (Of course I have
> barely tested it at all.)
> Is there any reason this *shouldn't* go into the next release?
>
>> source("image.R")
>> z <- matrix(runif(1e6),nrow=1000)
>> image(z)
>> image(z,useRaster=TRUE)
>
> (Patch against SVN 54284 attached; people can contact me if it doesn't
> go through and they want it.)
>
> Ben Bolker
>
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