The survexp function can fail when called from another function. The "why" of
this has me baffled, however.
Here is a simple test case, using a very stripped down version of survexp:
survexp.test <- function(formula, data,
weights, subset, na.action, rmap,
times, cohort=TRUE, conditional=FALSE,
ratetable=survexp.us, scale=1, npoints, se.fit,
model=FALSE, x=FALSE, y=FALSE) {
call <- match.call()
m <- match.call(expand.dots=FALSE)
# keep the first element (the call), and the following selected arguments
m <- m[c(1, match(c('formula', 'data', 'weights', 'subset', 'na.action'),
names(m), nomatch=0))]
m[[1]] <- as.name("model.frame")
# Add in the ratetable variables
varlist <- attr(ratetable, 'dimid')
tform <- paste(deparse(formula), paste(varlist, collapse='+'), sep='+')
m$formula <- tform
print(m)
print(ls(parent.frame()))
mf <- eval(m, parent.frame())
names(mf)
}
Here is the test data
tdata <- data.frame(age= c(12, 24, 36)*365.25, sex=c(1,2,1),
year=as.Date('1953/03/10', '1960/02/23', '1978/09.22'))
tfun <- function(mydata) {
zed <- 100 + (1:nrow(mydata)) * 20
survexp.test(zed ~ 1, data=mydata)
}
And the result of the exercise.
% R --vanilla
R version 2.11.0 (2010-04-22)
> library(survival) # to pick up the survexp.us data
> tfun(tdata)
model.frame(formula = "zed ~ 1+age+sex+year", data = mydata)
[1] "mydata" "zed"
Error in eval(expr, envir, enclos) : object 'zed' not found
-----
Eval is being called with the expression shown and an environment that
contains the relevant variables in that expression: zed and mydata. Yet it
fails to find the variable zed.
I don't see anything relevant in the manual pages for either eval or
model.frame. I suspect that there is an invisible, undocumented, magic
argument somewhere.
My second problem is a puzzler:
> options(error=recover)
> tfun(tdata)
model.frame(formula = "zed ~ 1+age+sex+year", data = mydata)
[1] "mydata" "zed"
Error in eval(expr, envir, enclos) : object 'zed' not found
Enter a frame number, or 0 to exit
1: tfun(tdata)
2: survexp.test(zed ~ 1, data = mydata)
3: eval(m, parent.frame())
4: eval(expr, envir, enclos)
5: model.frame(formula = "zed ~ 1+age+sex+year", data = mydata)
6: model.frame.default(formula = "zed ~ 1+age+sex+year", data = mydata)
7: eval(predvars, data, env)
8: eval(expr, envir, enclos)
Selection: 2
Called from: model.frame.default(formula = "zed ~ 1+age+sex+year", data =
mydata)
Why does selecting "2" result in going to frame "6"?
Terry Therneau
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