Thanks very much!
Fábio Mathias Corrêa UFLA
--- Em qua, 1/7/09, Kjell Konis <kjell.ko...@epfl.ch> escreveu:
De: Kjell Konis <kjell.ko...@epfl.ch>
Assunto: Re: [Rd] Matrix with random number
Para: "Fabio Mathias" <fabio.u...@yahoo.com.br>
Cc: r-devel@r-project.org
Data: Quarta-feira, 1 de Julho de 2009, 8:30
Hi Fabio,
Your function myrbeta returns void so assigning the output isn't going to
work. Instead you need to call it like a FORTRAN subroutine. Also, I added
arguments for the parameters of the beta and moved the fseedi and fseedo calls
outside of the loop.
This is a pretty basic FORTRAN programming question and there are lots of books
that can help you learn FORTRAN.
subroutine mat(x,l,c,pa,pb)
integer l,c
double precision x(l,c), a
integer i,j
call fseedi()
do j = 1, c
do i = 1, l
call myrbeta(x(i,j),pa,pb)
enddo
enddo
call fseedo()
end
In R call it like this:
storage.mode(x) <- "double"
..Fortran("mat", x = x, as.integer(l), as.integer(c), as.double(1),
as.double(2))
Cheers,
Kjell
On 30 juin 09, at 20:02, Fabio Mathias wrote:
> Thanks Mr. Barry Rowlingson
>
> However, the matrix appears to zeros!
>
> Notice the code below! Please!
>
> Code in fortran
>
> subroutine mat(x,l,c,a)
> integer l,c
> double precision x(l,c), a
> integer i,j
> do j = 1, c
> do i = 1, l
> call fseedi()
> x(i,j) = myrbeta(a,1,2)
> call fseedo()
> enddo
> enddo
> end
>
> In R:
>
> dyn.load("func.so")
> x <- matrix(0,5,6)
> l <- nrow(x)
> c <-
> ncol(x)
> a <- 0
>
> ..Fortran("mat", x = x, l, c, as.double(a))
>
> Results:
>
> $x
> [,1] [,2] [,3] [,4] [,5] [,6]
> [1,] 0 0 0 0 0 0
> [2,] 0 0 0 0 0 0
> [3,] 0 0 0 0 0 0
> [4,] 0 0 0 0 0 0
> [5,] 0 0 0 0 0 0
>
> [[2]]
> [1] 5
>
> [[3]]
> [1] 6
>
> [[4]]
> [1] 1
>
>
> Thanks!!!
>
>
> Fábio Mathias Corrêa UFLA
>
>
>
>
>
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