Martin Maechler wrote:
>If you specify max$all as "100%", i.e, as 0.9999 ('< 1' !) everything works
>as you expect it:
>
>agrep(pattern, subject, max = list(ins=0, del=0, sub= 2, all = 0.9999))
>## --> 2 3 4
>
>
OK I got it! Thanks for the explanation.
Cheers,
Hervé
--
------------------------
Hervé Pagès
E-mail: [EMAIL PROTECTED]
Phone: (206) 667-5791
Fax: (206) 667-1319
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