Whis is there a .Machine$sizeof.longdouble but no .Machine$sizeof.double?

(.Machine$double.digits + .Machine$double.exponent) / 8
could be used for .Machine$sizeof.double, I guess, but why define the
structure of doubles in bits, and all other sizeof's in bytes (e.g.,
.Machine$size.long)?

efg
Stowers Institute for Medical Research

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