Richard Henderson <[email protected]> writes:
> On 7/21/20 11:28 PM, Alex Bennée wrote:
>> + size_t phys_mem = qemu_get_host_physmem();
>> + if (phys_mem > 0 && phys_mem < (2 * DEFAULT_CODE_GEN_BUFFER_SIZE)) {
>> + tb_size = phys_mem / 8;
>> + } else {
>> + tb_size = DEFAULT_CODE_GEN_BUFFER_SIZE;
>> + }
>
> I don't understand the 2 * DEFAULT part.
I figured once you had at least twice as much memory you could use the
full amount but...
> Does this make more sense as
>
> if (phys_mem == 0) {
> tb_size = default;
> } else {
> tb_size = MIN(default, phys_mem / 8);
> }
This is probably a less aggressive tapering off which still doesn't
affect my 32gb dev machine ;-)
--
Alex Bennée
