"PAolo" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED]
> for i in range(1,10):
> if i%2:
> odd.append(i)
> else:
> even.append(i)
In 2.5 you'll be able to say
for i in range(1,10):
(odd if i%2 else even).append(i)
Whether you want to do this is another question entirely, of course.
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