"Peter Otten" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> sufficiently similar
I think I understand your points now.
But I wanted to match these cases:
>>> import operator
>>> reduce(operator.add,[],42)
42
>>> reduce(operator.add,[1],42)
43
The idea is that the i-th yield of i-reduce shd be the
result of reduce on seq[:i] with the given initializer.
That said, for the applications I first intended,
yes it is sufficiently similar. For now, I'll stick
with the version below.
Thanks,
Alan
def ireduce(func, iterable, init=None):
iterable = iter(iterable)
if init is None:
init = iterable.next()
yield init
else:
try:
init = func(init, iterable.next())
yield init
except StopIteration:
yield init
for item in iterable:
init = func(init, item)
yield init
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