Sebastjan Trepca wrote:
> is there any library or some way to parse dictionary string with list,
> string and int objects into a real Python dictionary?
>
> For example:
>
> >>> my_dict = dict_parser("{'test':'123','hehe':['hooray',1]}")
>
> I could use eval() but it's not very fast nor secure.
it's definitely slower than eval (which is written in C, after all), but it's
definitely more limited, and hopefully also more secure:
import cStringIO
import tokenize
def _parse(token, src):
if token[1] == "{":
out = {}
token = src.next()
while token[1] != "}":
key = _parse(token, src)
token = src.next()
if token[1] != ":":
raise SyntaxError("malformed dictionary")
value = _parse(src.next(), src)
out[key] = value
token = src.next()
if token[1] == ",":
token = src.next()
return out
elif token[1] == "[":
out = []
token = src.next()
while token[1] != "]":
out.append(_parse(token, src))
token = src.next()
if token[1] == ",":
token = src.next()
return out
elif token[0] == tokenize.STRING:
return token[1][1:-1].decode("string-escape")
elif token[0] == tokenize.NUMBER:
try:
return int(token[1], 0)
except ValueError:
return float(token[1])
else:
raise SyntaxError("malformed expression")
def myeval(source):
src = cStringIO.StringIO(source).readline
src = tokenize.generate_tokens(src)
return _parse(src.next(), src)
print myeval("{'test':'123','hehe':['hooray',0x10]}")
{'test': '123', 'hehe': ['hooray', 16]}
hope this helps!
</F>
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