<[EMAIL PROTECTED]> wrote:
...
> Rather than writing
>
> cellboard[0] is not* (cellboard[1] and cellboard[2] and cellboard[3]
> and cellboard[4] ... cellboard[8])
> cellboard[1] is not (cellboard[0] and cellboard[2] and cellboard[3] and
> cellboard[4] ... cellboard[8])
Urgh... the fastest way to check that a list of N numbers has no
duplicates is:
if len(set(thelist)) == len(thelist):
print 'no duplicates'
But if your purpose is to generate N random samples out of a population
of M, look at function random.sample (in module random in the Pythons
standard library) and you'll do even better!-)
Alex
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