but:
li = [grp for k, grp in groupby("aahfffddssssnnb")]
list(li[0])
[]
list(li[1])
[]
It seems empty ... I don't understand why, this is
the first read of an iterator, it should provide its
data.
The group-iterators are connected. Each group-iterator is a wrapper
around the original iterator
with an extra termination condition. So in order to start the next
group-iterator the previous
group-iterator is exhausted, because the original iterator has to be
ready to produce values
for the next group-iterator.
--
Antoon Pardon.
--
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