Let's say I define a list of pairs as follows:
>>l = [('d', 3), ('a', 2), ('b', 1)]
Can anyone explain why this does not work?
>>h = {}.update(l)
and instead I have to go:
>>h = {}
>>h.update(l)
to initialize a dictionary with the given list of pairs?
when an analagous operation on strings works fine:
>>s = "".join(["d","o","g"])
Seems inconsistent.
thanks,
Scott
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