Kaka wrote:
> for i in range(len(A.hp)):
>
> for j in range(len(run_parameters.bits_Mod)):
> req_slots[j] = math.ceil((A.T[i])
>
> for g in Temp[i]["Available_ranges"][j]:
> for s in range(g[0], g[-1]):
> if (s+req_slots[j]-1) <= g[-1]:
> if (Temp[i]['cost'][j] <= (run_parameters.PSD): ------
> When this condition is true i want to break the nested
> loop and start from the begining
> served_count +=1
> A.T[i]["First_index"]= s
> A.T[i]["Last_index"]= s+req_slots[j]-1
> A.T[i]["Status"]= 1
> A.T[i]["Selected_MOD"] = j
> break
Thou shalt indent four spaces. One shalt thou not indent excepting that thou
then proceed to four.
> I have this code. When the last "if" condition is satisfied, i want to
> break all the loops and start the nested loop for next i. else, the loop
> should continue.
>
> can anyone help me?
Option 1: Collaps your inner loops into a generator:
gen(a):
for b in ...:
for c in ...:
yield a, b, c
for a in ...:
for b, c in gen(a):
if f(a, b, c):
...
break
Option 2: If your code is too messy for option 1, use a helper function:
def process(a):
for b in ...:
for c in ...:
if f(a, b, c):
...
return
for a in ...:
process(a)
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