Tom Anderson wrote:
> Only one socket can be bound to a given port at any time, so the second
> instance of SpecialClass will get an exception from the bind call, and
> will be stillborn. This is a bit of a crufty hack, though - you end up
> with an open port on your machine for no good reason. If
If you bind with self.sock.bind(('localhost', 4242)) instead, at least
you don't have much of a security risk since the port won't be available
for connections from outside the same machine. Using '' instead of
'localhost' means bind to *all* interfaces, not just the loopback one.
-Peter
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